High Performance Computing 1
A sample sequence
•x0 =79, N = 100, P1 = 263, and P2 = 71
•x1 = 79*263 + 71 (mod 100) = 20848 (mod 100) = 48,
•x2 = 48*263 + 71 (mod 100) = 12695 (mod 100) = 95,
•x3 = 95*263 + 71 (mod 100) = 25056 (mod 100) = 56,
•x4 = 56*263 + 71 (mod 100) = 14799 (mod 100) = 99,
•Subsequent numbers are: 8, 75, 96, 68, 36, 39, 28, 35, 76, 59, 88, 15, 16, 79, 48.
•The sequence then repeats